2. The correct answer is . In this question, we are given that one square, A, has sides of length x and a second square, B, has sides of twice this length , and we are asked to compare the area of A to one half the area of B. The first thing you should do is draw a diagram. If you draw the squares somewhat carefully, the answer becomes obvious.
Figured out mathematically, the area of a square is the side squared. Column A will, then, yield a square with area x2. Column B will yield a square with area 4x2. x2 compared to 2x2 gives us an answer choice of because 2x2 is greater. You could have picked numbers for the sides of the squares and would have still come out with Column B being greater.
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